A conducting ring of radius r is rolling without slipping with a constant angular…
Physics · JEE Main · NTA Exams — Electromagnetic Induction and Alternating Currents
A conducting ring of radius r is rolling without slipping with a constant angular velocity ω in figure. If the magnetic field strength is B and is directed into the page then the e.m.f. induced across PQ is
- Bωr2
- \(\frac{B \omega r^{2}}{2}\)
- 4Bωr2
- \(\frac{\pi^{2} \mathrm{r}^{2} \mathrm{~B} \omega}{8}\)
Answer
(A) B ω r 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- In an a.c. circuit, V and I are given by V = 100 sin (100 t) volt I = 100 sin (100 t + π /3) mA. The power…
- The instantaneous magnetic flux φ in a circuit is φ = 4t 2 – 4t + 1. The total resistance of circuit is 10 Ω…
- Which of the following curves, figure correctly represent the variation of capacitive reactance (X C ) with…
- A parallel plate capacitor has circular plates each of radius 5 cm. It is being charged so that electric…
- How much current will flow in a circuit having resistance of 109 Ω and an inductance of 0.5 H connected to an…
- The average power dissipation in a pure capacitor in AC circuit is
- A long solenoid has 500 turns. When a current of 2 A is passed through it, the resulting magnetic flux linked…
- What is the value of inductance L for which the current is a maximum in a series LCR circuit with C = 10 μF…
More Electromagnetic Induction and Alternating Currents questions · Browse all practice questions