In an a.c. circuit, V and I are given by V = 100 sin (100 t) volt I = 100 sin (100 t + π…
Physics · JEE Main · NTA Exams — Electromagnetic Induction and Alternating Currents
In an a.c. circuit, V and I are given by
V = 100 sin (100 t) volt
I = 100 sin (100 t + π/3) mA.
The power dissipated in the circuit is
V = 100 sin (100 t) volt
I = 100 sin (100 t + π/3) mA.
The power dissipated in the circuit is
- 104 watt
- 10 watt
- 2.5 watt
- 5 watt
Answer
(C) 2.5 watt
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