The instantaneous magnetic flux φ in a circuit is φ = 4t 2 – 4t + 1. The total resistance…
Physics · JEE Main · NTA Exams — Electromagnetic Induction and Alternating Currents
The instantaneous magnetic flux φ in a circuit is φ = 4t2 – 4t + 1. The total resistance of circuit is 10 Ω. At \(\mathrm{t}=\frac{1}{2} \mathrm{~s},\) the induced current in circuit is
- 0
- 0.6
- 0.4
- 0.2
Answer
(A) 0
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