In a uniform magnetic field of induction B , a wire in the form of semicircle of radius r…
Physics · JEE Main · NTA Exams — Electromagnetic Induction and Alternating Currents
In a uniform magnetic field of induction B, a wire in the form of semicircle of radius r rotates about the diameter of the circle with angular frequency ω. If the total resistance of the circuit is R, the mean power generated per period of rotation is
- \(\frac{\mathrm{B} \pi \mathrm{r}^{2} \omega}{2 \mathrm{R}}\)
- \(\frac{\left(\mathrm{B} \pi \mathrm{r}^{2} \omega\right)^{2}}{8 \mathrm{R}}\)
- \(\frac{(\mathrm{B} \pi \mathrm{r} \omega)^{2}}{8 \mathrm{R}}\)
- \(\frac{\left(\mathrm{B} \pi \mathrm{r} \omega^{2}\right)^{2}}{8 \mathrm{R}}\)
Answer
(B) ( B r ^ 2 )^ 2 8 R
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