A series LCR circuit is tuned to resonance. The impedance of the circuit now is

Physics · JEE Main · NTA ExamsElectromagnetic Induction and Alternating Currents

A series LCR circuit is tuned to resonance. The impedance of the circuit now is
  1. \[\left[\mathrm{R}^{2}+\left(\omega \mathrm{L}-\frac{1}{\omega \mathrm{C}}\right)^{2}\right]^{1 / 2}\]
  2. \[\left[\mathrm{R}^{2}+(\omega \mathrm{L})^{2}+\left(\frac{1}{\omega \mathrm{C}}\right)^{2}\right]^{1 / 2}\]
  3. \[\left[\mathrm{R}^{2}+\left(\frac{1}{\omega \mathrm{C}}-\omega \mathrm{L}\right)^{2}\right]^{1 / 2}\]
  4. R

Answer

(D) R

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