A series LCR circuit is tuned to resonance. The impedance of the circuit now is
Physics · JEE Main · NTA Exams — Electromagnetic Induction and Alternating Currents
A series LCR circuit is tuned to resonance. The impedance of the circuit now is
- \[\left[\mathrm{R}^{2}+\left(\omega \mathrm{L}-\frac{1}{\omega \mathrm{C}}\right)^{2}\right]^{1 / 2}\]
- \[\left[\mathrm{R}^{2}+(\omega \mathrm{L})^{2}+\left(\frac{1}{\omega \mathrm{C}}\right)^{2}\right]^{1 / 2}\]
- \[\left[\mathrm{R}^{2}+\left(\frac{1}{\omega \mathrm{C}}-\omega \mathrm{L}\right)^{2}\right]^{1 / 2}\]
- R
Answer
(D) R
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