In an LR circuit, current falls to 19 times the initial value in a time T during the…
Physics · JEE Main · NTA Exams — Electromagnetic Induction and Alternating Currents
In an LR circuit, current falls to 19 times the initial value in a time T during the decay of current, then the value of the time constant is
- \(\frac{\mathrm{T}}{\operatorname{In}\left(\frac{1}{19}\right)}\)
- \(\frac{T}{\operatorname{In}(19)}\)
- \(\ln \left(\frac{1}{19}\right)\)
- \(\text { T In (19) }\)
Answer
(B) T In (19)
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