Assertion : Shortest distance between | x | + | y | = 2 & x 2 + y 2 = 16 is 4- 2 Reason …
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Assertion : Shortest distance between
| x | + | y | = 2 & x2 + y2 = 16 is \(4-\sqrt{2}\)
Reason : Shortest distance between the two non intersecting differentiable curves lies along the common normal.
| x | + | y | = 2 & x2 + y2 = 16 is \(4-\sqrt{2}\)
Reason : Shortest distance between the two non intersecting differentiable curves lies along the common normal.
- If Assertion is true, Reason is true, Reason is a correct explanation for Assertion.
- If Assertion is true, Reason is true, Reason is not a correct explanation for Assertion.
- If Assertion is true, Reason is false.
- If Assertion is false, Reason is true.
Answer
(D) If Assertion is false, Reason is true.
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