The value of _ x 1 (1-x) ( x 2 ) will be
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The value of \(\lim _{x \rightarrow 1}(1-x) \cdot \tan \left(\frac{\pi x}{2}\right)\) will be
- \(\frac{\pi}{2}\)
- \(\frac{2}{\pi}\)
- 2\(\pi\)
- \(\pi\)
Answer
(B) 2
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