_ n (0.2)^ _ 5 ( 1 4 + 1 8 + 1 16 + ton terms ) is equal to
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\(\lim _{n \rightarrow \infty}(0.2)^{\log _{\sqrt{5}}\left(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\ldots \text { ton terms }\right)}\)is equal to
- 2
- 4
- 8
- 0
Answer
(B) 4
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