A function is matched below against an interval where it is supposed to be increasing…

Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability

1. Interval : \([Z, \infty)\)  --   Function : \(2 x^{3}-3 x^{2}-12 x+6\)
2. Interval : \((-\infty, 1-\sqrt{2}]\)  --  Function : \(\mathbf{x}^{3}-3 \mathbf{x}^{2}-3 \mathbf{x}+3\)
3. Interval : \((-\infty,-4]\)  --  Function : \(x^{3}+6 x^{2}+6\)
4. Interval : \(\left(-\infty, \frac{1}{3}\right)\)  --  Function : \(3 x^{2}-2 x+1\)

Answer

(D) Interval : (- , 1 3 ) -- Function : 3 x^ 2 -2 x+1

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