If for x (0, 1 4 ) , the derivative of ^ -1 ( 6 x x 1-9 x^ 3 ) is x g(x) then g(x) equals
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If for \(x \in\left(0, \frac{1}{4}\right)\), the derivative of \(\tan ^{-1}\left(\frac{6 x \sqrt{x}}{1-9 x^{3}}\right)\) is \(\sqrt{x} g(x)\) then g(x) equals
- \(\frac{3 x \sqrt{x}}{1-9 x^{3}}\)
- \(\frac{3 x}{1-9 x^{3}}\)
- \(\frac{3}{1+9 x^{3}}\)
- \(\frac{9}{1+9 x^{3}}\)
Answer
(D) 9 1+9 x^ 3
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