Limit _ x 0^ + (1+ ^ 2 x )^ 5 / x =
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\(\operatorname{Limit}_{x \rightarrow 0^{+}}\left(1+\tan ^{2} \sqrt{x}\right)^{5 / x}=\)
- e5
- e2
- e
- none
Answer
(A) e 5
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