The minimum value of a tan 2 x + b cot 2 x equals the maximum value of a sin 2 θ + b cos…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The minimum value of a tan2 x + b cot2 x equals the maximum value of a sin2 θ + b cos2 θ where a > b > 0, when
- a = b
- a = 2b
- a = 3b
- a = 4b
Answer
(D) a = 4b
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