Let f (x) = array lll -x^ 2 , & for & x y = f (x) is
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Let f (x) = \(\left\{\begin{array}{lll}
-x^{2}, & \text { for } & x<0 \\
x^{2}+8, & \text { for } & x \geq 0
\end{array} .\right.\) Then the x-intercept of the line that is tangent to both portions of the graph of
y = f (x) is
y = f (x) is
- zero
- –1
- –3
- –4
Answer
(B) –1
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