The value of _ x 0 x x- (1+x) x^ 2 is
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The value of \(\lim _{x \rightarrow 0} \frac{x \cos x-\log (1+x)}{x^{2}}\) is
- 1/2
- 0
- 1
- None of these
Answer
(A) 1/2
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