The value of _ x 0 1 x^ 3 _ 0 ^ x t (1+t) t^ 4 +4 d t i 5 ,
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The value of \(\lim _{x \rightarrow 0} \frac{1}{x^{3}} \int_{0}^{x} \frac{t \cdot \log (1+t)}{t^{4}+4} d t \mathrm{i} 5\),
- 0
- \(\frac{1}{12}\)
- \(\frac{1}{24}\)
- \(\frac{1}{64}\)
Answer
(C) 1 24
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