The curves x 3 + p xy 2 = –2 and 3x 2 y – y 3 = 2 are orthogonal for
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The curves x3 + p xy2 = –2 and 3x2y – y3 = 2 are orthogonal for
- p = 3
- p = –3
- no value of p
- p = +3
Answer
(B) p = –3
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