Let f (x) be the function given by f(x)=3 x^ 5 -5 x^ 3 +21 x+3 x+4 x+5 . Then,

Mathematics · JEE Main · NTA ExamsLimit, Continuity and Differentiability

Let f (x) be the function given by \(f(x)=3 x^{5}-5 x^{3}+21 x+3 \sin x+4 \cos x+5\). Then,
  1. f (x) is increasing on R and \(f(x)=0\) has exactly one negative root
  2. f (x) is decreasing on R and \(f(x)=0\) has exactly one positive root
  3. f (x) is decreasing and \(f(x)=0\) has exactly one negative root
  4. f (x) is increasing and \(f(x)=0\) has exactly one positive root.

Answer

(D) f (x) is increasing and f(x)=0 has exactly one positive root.

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Limit, Continuity and Differentiability questions · Browse all practice questions