Let f (x) be the function given by f(x)=3 x^ 5 -5 x^ 3 +21 x+3 x+4 x+5 . Then,
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Let f (x) be the function given by \(f(x)=3 x^{5}-5 x^{3}+21 x+3 \sin x+4 \cos x+5\). Then,
- f (x) is increasing on R and \(f(x)=0\) has exactly one negative root
- f (x) is decreasing on R and \(f(x)=0\) has exactly one positive root
- f (x) is decreasing and \(f(x)=0\) has exactly one negative root
- f (x) is increasing and \(f(x)=0\) has exactly one positive root.
Answer
(D) f (x) is increasing and f(x)=0 has exactly one positive root.
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