The two curves x 3 – 3xy 2 + 2 = 0 and 3x 2 y – y 3 – 2 = 0
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The two curves x3 – 3xy2 + 2 = 0 and 3x2y – y3 – 2 = 0
- cut at right angles
- touch each other
- cut at an angle \(\frac{\pi}{3}\)
- cut at an angle \(\frac{\pi}{4}\)
Answer
(A) cut at right angles
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