The two curves x 3 – 3xy 2 + 2 = 0 and 3x 2 y – y 3 – 2 = 0

Mathematics · JEE Main · NTA ExamsLimit, Continuity and Differentiability

The two curves x3 – 3xy2 + 2 = 0 and 3x2y – y3 – 2 = 0
  1. cut at right angles
  2. touch each other
  3. cut at an angle \(\frac{\pi}{3}\)
  4. cut at an angle \(\frac{\pi}{4}\)

Answer

(A) cut at right angles

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