Slope of tangent to the curve y = 2e x sin ( 4 - x 2 ) cos ( 4 - x 2 ), where 0 ≤ x ≤ 2π…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Slope of tangent to the curve
y = 2ex sin \(\left(\frac{\pi}{4}-\frac{x}{2}\right)\) cos \(\left(\frac{\pi}{4}-\frac{x}{2}\right),\)where 0 ≤ x ≤ 2π is minimum at x =
y = 2ex sin \(\left(\frac{\pi}{4}-\frac{x}{2}\right)\) cos \(\left(\frac{\pi}{4}-\frac{x}{2}\right),\)where 0 ≤ x ≤ 2π is minimum at x =
- 0
- π
- 2π
- none of these
Answer
(B) π
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