If _ x ( x^ 2 -1 x+1 -a x-b )=2 , then find the value of b .
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If \(\lim _{x \rightarrow \infty}\left(\frac{x^{2}-1}{x+1}-a x-b\right)=2\), then find the value of \(\text { b }\).
- \(b=2\)
- \(b=-3\)
- \(b=3\)
- \(b=1\)
Answer
(C) b=3
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