How many real solutions does the equation x 7 + 14x 5 + 16x 3 + 30x – 560 = 0 have ?
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
How many real solutions does the equation
x7 + 14x5 + 16x3 + 30x – 560 = 0 have ?
x7 + 14x5 + 16x3 + 30x – 560 = 0 have ?
- 5
- 7
- 1
- 3
Answer
(C) 1
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