The two tangents to the curve ax 2 + 2hxy + by 2 = 1, a > 0 at the points where it…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The two tangents to the curve ax2 + 2hxy + by2 = 1, a > 0 at the points where it crosses x-axis, are
- parallel
- perpendicular
- inclined at an angle \(\frac{\pi}{4}\)
- none of these
Answer
(A) parallel
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The minimum value of a tan 2 x + b cot 2 x equals the maximum value of a sin 2 θ + b cos 2 θ where a > b > 0…
- If f_ n (x)=e^ f_ n-1 |x| for all n ∈ N and f_ n (x)=x , then d d x f_ n (x) is equal to:
- For x (0, ^ -1 5 2 ) , the function f (x) = cot –1 ( 2 x+ 5 x 7 )
- If f^ (x)=g(x) and g^ (x)=-f(x) V x and f(2)=4=f^ (2) , then f^ 2 (19)+g^ 2 (19) is
- _ x 0 3^ x -2^ x 4^ x -3^ x is equal to
- The point on the curve y-e^ x y +x=0 at which curve have vertical tangent is
- _ x 3 ([x-3]+[3-x]-x), where [.] denotes the greatest integer function, is equal to
- For x R, f(x)=| 2- x| and g(x)=f(f(x)) then :
More Limit, Continuity and Differentiability questions · Browse all practice questions