If y= [ ^ -1 1 1+x+x^ 2 + ^ -1 1 x^ 2 +3 x+3 + . .+ ^ -1 1 x^ 2 +5 x+7 + . upton terms ]…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If \(y=\left[\tan ^{-1} \frac{1}{1+x+x^{2}}+\tan ^{-1} \frac{1}{x^{2}+3 x+3}+\right.\)
\(\left.+\tan ^{-1} \frac{1}{x^{2}+5 x+7}+\ldots . \text { upton terms }\right]\)then \(\mathrm{y}^{\prime}(0)\)equals
\(\left.+\tan ^{-1} \frac{1}{x^{2}+5 x+7}+\ldots . \text { upton terms }\right]\)then \(\mathrm{y}^{\prime}(0)\)equals
- \(\frac{-1}{\mathrm{n}^{2}+1}\)
- \(\frac{-n^{2}}{n^{2}+1}\)
- \(\frac{\mathrm{n}^{2}}{\mathrm{n}^{2}+1}\)
- None of these
Answer
(B) -n^ 2 n^ 2 +1
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