Consider the function f (x) = max x 2 , (1 – x) 2 , 2x (1 – x) where 0 ≤ x ≤ 1 . The…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Consider the function f (x) = max {x2, (1 – x)2, 2x (1 – x)}
where 0 ≤ x ≤ 1 .
The interval in which f (x) is increasing is
- \(\left(\frac{1}{3}, \frac{2}{3}\right)\)
- \(\left(\frac{1}{3}, \frac{1}{2}\right)\)
- \(\left(\frac{1}{3}, \frac{1}{2}\right) \cup\left(\frac{1}{2}, \frac{2}{3}\right)\)
- \(\left(\frac{1}{3}, \frac{1}{2}\right) \cup\left(\frac{2}{3}, 1\right)\)
Answer
(D) ( 1 3 , 1 2 ) ( 2 3 , 1 )
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