The value of _ x 1 (2-x)^ x 2 is equal to...

Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability

1. ^{\(\mathrm{e}^{\frac{-2}{\pi}}\)}
2. ^{\(\mathbf{e}^{\frac{1}{\pi}}\)}
3. ^{\(\mathbf{e}^{\frac{2}{\pi}}\)}
4. ^{\(\mathbf{e}^{\frac{-1}{\pi}}\)}

Answer

(A) e ^ -2

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