A block of mass m is pushed towards a movable wedge of mass nm and height h, with a…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A block of mass m is pushed towards a movable wedge of mass nm and height h, with a velocity u. All surfaces are smooth. The minimum value of u for which the block will reach the top of the wedge is :


- \(\sqrt{2 \mathrm{gh}}\)
- \(\sqrt{2 \mathrm{ngh}}\)
- \(\sqrt{2 g h\left(1+\frac{1}{n}\right)}\)
- \(\sqrt{2 g h\left(1-\frac{1}{n}\right)}\)
Answer
(C) 2 g h (1+ 1 n )
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