In the figure, if F = 4N, m = 2kg, M = 4 kg then array l M =0 array
Physics · JEE Advanced · NTA Exams — Laws of Motion
In the figure, if F = 4N, m = 2kg, M = 4 kg then
\[\begin{array}{l} \text { M }\\ \mu=0 \end{array}\]
\[\begin{array}{l} \text { M }\\ \mu=0 \end{array}\]
- The acceleration of m w.r.t. ground is \(\frac{2}{3} m / s^{2} .\)
- The acceleration of m w.r.t. ground is 1.2 m/s2.
- The acceleration of M is 0.4 m/s2.
- The acceleration of M w.r.t. ground is \(\frac{2}{3} m / s^{2} .\)
Answer
(B) The acceleration of m w.r.t. ground is 1.2 m/s2., (C) The acceleration of M is 0.4 m/s2.
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