Three identical uniform rods of the same mass M and length L are arranged in xy plane as…
Physics · JEE Advanced · NTA Exams — Laws of Motion
Three identical uniform rods of the same mass M and length L are arranged in xy plane as shown. A fourth uniform rod of mass 3M has been placed as shown in the xy plane. What should be the value of the length of the fourth rod such that the center of mass of all the four rods lie at the origin ?
- 3L
- 2L
- \(\mathrm{L}(\sqrt{2}+1) / 3\)
- \(\frac{\mathrm{L}(2 \sqrt{2}+1)}{3}\)
Answer
(C) L ( 2 +1) / 3
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