A cracker is thrown into air with a velocity of 10 m/s at an angle of 45° with the…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A cracker is thrown into air with a velocity of 10 m/s at an angle of 45° with the vertical. When its is at a height of \(\left(\frac{1}{2}\right) \mathrm{m}\) from the ground, it explodes into a number of peices which follow different parabolic paths. What is the velocity of centre of mass, when its is at a height of 1 m from the ground ? (g = 10 m/s–2)
- \(4 \sqrt{5} \mathrm{~ms}^{-1}\)
- \(2 \sqrt{5} \mathrm{~ms}^{-1}\)
- \(5 \sqrt{4} \mathrm{~ms}^{-1}\)
- 5 ms–1
Answer
(A) 4 5 ~ms ^ -1
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