From a circular disc of radius R, a square is cut out with a radius as its diagonal. The…
Physics · JEE Advanced · NTA Exams — Laws of Motion
From a circular disc of radius R, a square is cut out with a radius as its diagonal. The centre of mass of remainder is at a distance (from the centre) :
- \(\frac{\mathrm{R}}{(4 \pi-2)}\)
- \(\frac{\mathrm{R}}{2 \pi}\)
- \(\frac{\mathrm{R}}{(\pi-2)}\)
- \(\frac{\mathrm{R}}{(2 \pi-2)}\)
Answer
(A) R (4 -2)
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