The points (–a, –b), (0, 0), (a, b) and (a 2 , ab) are
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
The points (–a, –b), (0, 0), (a, b) and (a2, ab) are
- collinear
- vertices of a rectangle
- vertices of a parallelogram
- None of the above
Answer
(A) collinear
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If the normal to the parabola y 2 = 4ax at the point (at 2 , 2at) cuts the parabola again at (aT 2 , 2aT)…
- The vertices of ∆OBC are respectively (0, 0), (–3, –1) and (–1, –3). The equation of line parallel to BC and…
- The equation of the circle passing through (1, 1) and the points of intersection of x 2 + y 2 + 13 x – 3y = 0…
- A tangent to the parabola x 2 + 4ay = 0 cuts the parabola x 2 = 4by at A and B the locus of the mid point of…
- The number of common tangents to the circles x 2 +y 2 = 4 and x 2 + y 2 – 6x – 8y = 24 is :
- For a > b > c > 0, the distance between (1, 1) and the point of intersection of the lines ax + by + c = 0 and…
- A straight line through the vertex P of a triangle PQR, intersects the side QR at the point S and the…
- Assertion : The perpendicular bisector of the line segment joining the point (–a, 2 at) and (a, 0) is tangent…
More Co-ordinate Geometry questions · Browse all practice questions