For a > b > c > 0, the distance between (1, 1) and the point of intersection of the lines…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
For a > b > c > 0, the distance between (1, 1) and the point of intersection of the lines ax + by + c = 0 and bx + ay + c = 0 is less than 
. Then
. Then- a + b – c > 0
- a – b + c < 0
- a – b + c > 0
- a + b – c < 0
Answer
(C) a – b + c > 0
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