The equation of the circle passing through (1, 1) and the points of intersection of x 2 +…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
The equation of the circle passing through (1, 1) and the points of intersection of x2 + y2 + 13 x – 3y = 0 and 2x2 + 2y2 + 4x – 7y – 25 = 0 is :
- 4x2 + 4y2 – 30x – 10 y = 25
- 4x2 + 4y2 + 30x – 13 y – 25 = 0
- 4x2 + 4y2 – 17x – 10 y + 25 = 0
- none of these
Answer
(B) 4x 2 + 4y 2 + 30x – 13 y – 25 = 0
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