The points on the curve y = x 1- x ^ 2 –1 < x < 1 at which the tangent line is vertical…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The points on the curve y = x \(\sqrt{1-\mathrm{x}^{2}}\) –1 < x < 1 at which the tangent line is vertical are
- (–1, 0)
- \(\left(-\frac{1}{\sqrt{2}},-\frac{1}{2}\right)\)
- (1, 0)
- \(\left(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right)\)
Answer
(A) (–1, 0), (C) (1, 0)
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