Limit _ n (n+2)!+(n+1)! (n+3)! , n ∈ N =
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\(\operatorname{Limit}_{n \rightarrow \infty} \frac{(n+2)!+(n+1)!}{(n+3)!},\) n ∈ N =
- 0
- 1
- 2
- –1
Answer
(A) 0
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