If x = 1-t^ 2 1+t^ 2 and y = 2 t 1+ t ^ 2 , then dy dx is equal to
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If x = \(\frac{1-t^{2}}{1+t^{2}}\) and y = \(\frac{2 \mathrm{t}}{1+\mathrm{t}^{2}},\) then \(\frac{\mathrm{dy}}{\mathrm{dx}}\) is equal to
- \(-\frac{y}{x}\)
- \(\frac{y}{x}\)
- \(-\frac{\mathrm{x}}{\mathrm{y}}\)
- \(\frac{x}{y}\)
Answer
(C) - x y
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