The equation of the tangent to the curve y= 9-2 x^ 2 at the point where the ordinate and…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The equation of the tangent to the curve \(y=\sqrt{9-2 x^{2}}\)at the point where the ordinate and the abscissa are equal, is
- \(2 x+y-3 \sqrt{3}=0\)
- \(2 x+y+3 \sqrt{3}=0\)
- \(2 x-y-3 \sqrt{3}=0\)
- none of these
Answer
(A) 2 x+y-3 3 =0
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