Smaller area enclosed by the circle x^ 2 +y^ 2 =4 and the line x+y=2 is :
Mathematics · JEE Main · NTA Exams — Integral Calculus
Smaller area enclosed by the circle \(x^{2}+y^{2}=4\) and the line \(x+y=2\) is :
- \(2(\pi-2)\)
- \(\pi-2\)
- \(2 \pi-1\)
- \(2(\pi+2)\)
Answer
(B) -2
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