The value of ( 6 1+x^ 2 +10^ x ) d x is
Mathematics · JEE Main · NTA Exams — Integral Calculus
The value of \(\int\left(\frac{6}{1+x^{2}}+10^{x}\right) d x\)is
- 6 tan–1 x + 10x loge 10 + C
- \(6 \tan ^{-1} x+\frac{10^{x}}{\log _{e} 10}+C\)
- \(3 \tan ^{-1} x+\frac{10^{x}}{\log _{e} 10}+C\)
- none of these
Answer
(B) 6 ^ -1 x+ 10^ x _ e 10 +C
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