I_ 1 = _ 1 ^ 2 e^ x d x and I_ 2 = _ 1 ^ 2 _ e x d x Then
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(I_{1}=\int_{1}^{2} e^{x} d x\) and \(I_{2}=\int_{1}^{2} \log _{e} x d x\) Then
- \(\mathrm{I}_{1}>\mathrm{I}_{2}\)
- \(\mathrm{I}_{1}<\mathrm{I}_{2}\)
- \(\mathrm{I}_{1}=\mathrm{I}_{2}\)
- None of these
Answer
(A) I _ 1 > I _ 2
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