I_ 1 = _ 0 ^ / 4 ^ 3 x d x and I_ 2 = _ 0 ^ / 4 ^ 5 x d x I_ 3 = _ 0 ^ / 4 ^ 1 / 2 x d x…
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(I_{1}=\int_{0}^{\pi / 4} \tan ^{3} x d x\)and\(I_{2}=\int_{0}^{\pi / 4} \tan ^{5} x d x\)
\(I_{3}=\int_{0}^{\pi / 4} \tan ^{1 / 2} x d x\) and \(I_{4}=\int_{0}^{\pi / 4} \tan ^{1 / 3} x d x\) then
\(I_{3}=\int_{0}^{\pi / 4} \tan ^{1 / 2} x d x\) and \(I_{4}=\int_{0}^{\pi / 4} \tan ^{1 / 3} x d x\) then
- \(\mathrm{I}_{1}<\mathrm{I}_{2}\)
- \(\mathrm{I}_{1}>\mathrm{I}_{3}\)
- \(\mathrm{I}_{3}>\mathrm{I}_{4}\)
- \(\mathrm{I}_{1}>\mathrm{I}_{2}\)
Answer
(D) I _ 1 > I _ 2
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