A uniform rod of length 2 l is placed with one end in contact with the horizontal table…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A uniform rod of length 2l is placed with one end in contact with the horizontal table and is then inclined at an angle a to the horizontal and allowed to fall. When it becomes horizontal, its angular velocity will be
- \(\sqrt{\frac{3 g \sin \alpha}{2 \ell}}\)
- \(\sqrt{\frac{2 \ell}{3 g \sin \alpha}}\)
- \(\sqrt{\frac{g \sin \alpha}{\ell}}\)
- \(\sqrt{\frac{\ell}{g \sin \alpha}}\)
Answer
(A) 3 g 2
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