A particle of mass m is attached to one end of a string of length l while the other end…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A particle of mass m is attached to one end of a string of length l while the other end is fixed to a point h above the horizontal table, the particle is made to revolve in a circle on the table so as to make p revolutions per second. The maximum value of p if the particle is to be in contact with the table will be-
- \(2 \pi \sqrt{\mathrm{gh}}\)
- \(\sqrt{(\mathrm{g} / \mathrm{h})}\)
- \(2 \pi \sqrt{(\mathrm{~h} / \mathrm{g})}\)
- \(\frac{1}{2 \pi} \sqrt{(\mathrm{~g} / \mathrm{h})}\)
Answer
(D) 1 2 ( ~g / h )
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