A uniform rod of mass m is bent into the form of a semicircle of radius R. The moment of…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A uniform rod of mass m is bent into the form of a semicircle of radius R. The moment of inertia of the rod about an axis passing through A and perpendicular to the plane of the paper is:
\[\mathbf{A}\]
\[\mathbf{A}\]
- \(\frac{2}{3} \mathrm{mR}^{2}\)
- mR2
- \(\frac{5}{\pi} \mathrm{mR}^{2}\)
- 2mR2
Answer
(D) 2mR 2
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