In the given figure, a uniform solid sphere is released on the top of a fixed inclined…
Physics · JEE Advanced · NTA Exams — Rotational Motion
In the given figure, a uniform solid sphere is released on the
top of a fixed inclined plane of inclination 37° and height ‘h’.
It rolls without sliding.
The acceleration of the centre of the sphere is
- \(\frac{3 g}{5}\)
- \(\frac{4 g}{5}\)
- \(\frac{4 g}{7}\)
- \(\frac{3 g}{7}\)
Answer
(D) 3 g 7
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