A heavy small sized sphere is suspended by a string of length  . The sphere rotates…

Physics · JEE Advanced · NTA Exams — Rotational Motion

1. T = 2π
2. T=2π \[\sqrt{\left(\frac{l \sin \theta}{\mathrm{~g}}\right)}\]
3. T = 2π \[\sqrt{\left(\frac{l \cos \theta}{\mathrm{~g}}\right)}\]
4. T=2π\[\sqrt{\left(\frac{l}{g \cos \theta}\right)}\]

Answer

(C) T = 2 π ( l ~g )

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