The image of the points (–1, 3, 4) in the plane x – 2y = 0 is
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The image of the points (–1, 3, 4) in the plane x – 2y = 0 is
- (15, 11, 4)
- \(\left(-\frac{17}{3},-\frac{19}{3}, 1\right)\)
- (8, 4, 4)
- \(\left(\frac{9}{5},-\frac{13}{5}, 4\right)\)
Answer
(D) ( 9 5 ,- 13 5 , 4 )
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