Angle between the vectors 2 i +6 j +3 k and 12 i -4 j +3 k is

Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry

1. \(\cos ^{-1}\left(\frac{1}{10}\right)\)
2. \(\cos ^{-1}\left(\frac{9}{11}\right)\)
3. \(\cos ^{-1}\left(\frac{9}{91}\right)\)
4. \(\cos ^{-1}\left(\frac{1}{9}\right)\)

Answer

(C) ^ -1 ( 9 91 )

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