Calculate the heat required to make 6.4 Kg CaC 2 from CaO(s) and C(s) from the reaction …
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
Calculate the heat required to make 6.4 Kg CaC2 from CaO(s) and C(s) from the reaction :
CaO(s) + 3 C(s) \(\text { → }\) CaC2(s) + CO(g) given that
CaO(s) + 3 C(s) \(\text { → }\) CaC2(s) + CO(g) given that
\(\Delta_{\mathrm{f}} \mathrm{H}^{\circ}(\mathrm{CaO})\) = –151.6 kcal, \(\Delta_{\mathrm{f}} \mathrm{H}^{\circ}\left(\mathrm{CaC}_{2}\right)\) = –14.2kcal.
\(\Delta_{\mathrm{f}} \mathrm{H}^{\circ}(\mathrm{CO})\) = –26.4 kcal.
- 5624 kcal
- 1.11 × 104 kcal
- 86.24 × 103
- 1100 kcal
Answer
(B) 1.11 × 10 4 kcal
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